This problem was asked by Google.
We can determine how "out of order" an array A is by counting the number of inversions it has. Two elements
A[j] form an inversion if
A[i] > A[j] but
i < j. That is, a smaller element appears after a larger element.
Given an array, count the number of inversions it has. Do this faster than
You may assume each element in the array is distinct.
For example, a sorted list has zero inversions. The array
[2, 4, 1, 3, 5] has three inversions:
(4, 1), and
(4, 3). The array
[5, 4, 3, 2, 1] has ten inversions: every distinct pair forms an inversion.