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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here's your problem today. This problem was recently asked by Apple:

Given a sorted array, convert it into a binary search tree.

Can you do this both recursively and iteratively?

class Node(object): def init(self, val, left=None, right=None): self.val = val self.left = left self.right = right def str(self): return f"{self.val}, ({self.left}, {self.right})"

class Solution(object): def sortedArrayToBST(self, nums): # Fill this in.

n = Solution().sortedArrayToBST([-10, -3, 0, 5, 9]) print(n)

0, (-3, (-10, (None, None), None), 9, (5, (None, None), None))