# Recca Chao 的 gitHub page

## 推廣網站開發，包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

Hi, here’s your problem today. This problem was recently asked by Twitter:

Given a Roman numeral, find the corresponding decimal value. Inputs will be between 1 and 3999.

Example: Input: IX Output: 9

Input: VII Output: 7

Input: MCMIV Output: 1904 Roman numerals are based on the following symbols: I 1 IV 4 V 5 IX 9 X 10 XL 40 L 50 XC 90 C 100 CD 400 D 500 CM 900 M 1000 Numbers are strings of these symbols in descending order. In some cases, subtractive notation is used to avoid repeated characters. The rules are as follows: 1.) I placed before V or X is one less, so 4 = IV (one less than 5), and 9 is IX (one less than 10) 2.) X placed before L or C indicates ten less, so 40 is XL (10 less than 50) and 90 is XC (10 less than 100). 3.) C placed before D or M indicates 100 less, so 400 is CD (100 less than 500), and 900 is CM (100 less than 1000).

class Solution(): def romanToInt(self, s): # Fill this in.

n = ‘MCMX’ print(Solution().romanToInt(n))