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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here’s your problem today. This problem was recently asked by Microsoft:

Given a node in a connected directional graph, create a copy of it.

Here’s an example and some starter code.

class Node: def init(self, value, adj=None): self.value = value self.adj = adj

# Variable to help print graph
self._print_visited = set()
if self.adj is None:
  self.adj = []

Able to print graph

def repr(self): if self in self._print_visited: return ‘’ else: self._print_visited.add(self) final_str = ‘’ for n in self.adj: final_str += f’{n}\n’

  return final_str + f'({self.value}, ({[n.value for n in self.adj]}))'

def deep_copy_graph(graph_node, visited=None):

Fill this in.

n5 = Node(5) n4 = Node(4) n3 = Node(3, [n4]) n2 = Node(2) n1 = Node(1, [n5]) n5.adj = [n3] n4.adj = [n3, n2] n2.adj = [n4] graph_copy = deep_copy_graph(n1) print(graph_copy)

(2, ([4]))

(4, ([3, 2]))

(3, ([4]))

(5, ([3]))

(1, ([5]))