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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here’s your problem today. This problem was recently asked by AirBNB:

Given a sorted array, A, with possibly duplicated elements, find the indices of the first and last occurrences of a target element, x. Return -1 if the target is not found.

Example:

Input: A = [1,3,3,5,7,8,9,9,9,15], target = 9
Output: [6,8]

Input: A = [100, 150, 150, 153], target = 150
Output: [1,2]

Input: A = [1,2,3,4,5,6,10], target = 9
Output: [-1, -1]

Here is a function signature example:

class Solution:

  def getRange(self, arr, target):
    # Fill this in.
  
# Test program 
arr = [1, 2, 2, 2, 2, 3, 4, 7, 8, 8] 
x = 2
print(Solution().getRange(arr, x))
# [1, 4]