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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here's your problem today. This problem was recently asked by Apple:

Given an integer k and a binary search tree, find the floor (less than or equal to) of k, and the ceiling (larger than or equal to) of k. If either does not exist, then print them as None.

Here is the definition of a node for the tree.

class Node:
  def __init__(self, value):
    self.left = None
    self.right = None
    self.value = value

def findCeilingFloor(root_node, k, floor=None, ceil=None):
  # Fill this in.

root = Node(8) 
root.left = Node(4) 
root.right = Node(12) 
root.left.left = Node(2) 
root.left.right = Node(6) 
root.right.left = Node(10) 
root.right.right = Node(14) 

print findCeilingFloor(root, 5)
# (4, 6)