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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here's your problem today. This problem was recently asked by Google:

Given a list of numbers, for each element find the next element that is larger than the current element. Return the answer as a list of indices. If there are no elements larger than the current element, then use -1 instead.

Here's an example and some starter code:

def larger_number(nums):
  # Fill this in.
  
# print [2, 2, 3, 4, -1, -1]
print(larger_number([3, 2, 5, 6, 9, 8]))