Recca Chao 的 gitHub page

推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here’s your problem today. This problem was recently asked by Microsoft:

Given a list of numbers of size n, where n is greater than 3, find the maximum and minimum of the list using less than 2 * (n - 1) comparisons.

Here’s a start:

def find_min_max(nums):

Fill this in.

print find_min_max([3, 5, 1, 2, 4, 8])

(1, 8)