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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here's your problem today. This problem was recently asked by Facebook:

Given a sorted list of numbers, return a list of strings that represent all of the consecutive numbers.

Example:

Input: [0, 1, 2, 5, 7, 8, 9, 9, 10, 11, 15]
Output: ['0->2', '5->5', '7->11', '15->15']

Assume that all numbers will be greater than or equal to 0, and each element can repeat.

Here is a starting point:

def findRanges(nums):
  # Fill this in.

print findRanges([0, 1, 2, 5, 7, 8, 9, 9, 10, 11, 15])
# ['0->2', '5->5', '7->11', '15->15']