Hi, here's your problem today. This problem was recently asked by LinkedIn:
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Given a binary tree, find the most frequent subtree sum.
3 / \ 1 -3
The above tree has 3 subtrees. The root node with 3, and the 2 leaf nodes, which gives us a total of 3 subtree sums. The root node has a sum of 1 (3 + 1 + -3), the left leaf node has a sum of 1, and the right leaf node has a sum of -3. Therefore the most frequent subtree sum is 1.
If there is a tie between the most frequent sum, you can return any one of them.
Here's some starter code for the problem:
class Node(): def __init__(self, value, left=None, right=None): self.val = value self.left = left self.right = right def most_freq_subtree_sum(root): # fill this in. root = Node(3, Node(1), Node(-3)) print(most_freq_subtree_sum(root)) # 1