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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here's your problem today. This problem was recently asked by Facebook:

Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.

Example:

Input: [0,1,0,3,12]
Output: [1,3,12,0,0]

You must do this in-place without making a copy of the array. Minimize the total number of operations.

Here is a starting point:

class Solution:
  def moveZeros(self, nums):
    # Fill this in.

nums = [0, 0, 0, 2, 0, 1, 3, 4, 0, 0]
Solution().moveZeros(nums)
print(nums)
# [2, 1, 3, 4, 0, 0, 0, 0, 0, 0]