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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here’s your problem today. This problem was recently asked by Microsoft:

Given a valid parenthesis string (with only ‘(’ and ‘)’, an open parenthesis will always end with a close parenthesis, and a close parenthesis will never start first), remove the outermost layers of the parenthesis string and return the new parenthesis string.

If the string has multiple outer layer parenthesis (ie (())()), remove all outer layers and construct the new string. So in the example, the string can be broken down into (()) + (). By removing both components outer layer we are left with () + ‘’ which is simply (), thus the answer for that input would be ().

Here are some examples and some starter code.

def remove_outermost_parenthesis(s):

Fill this in.






’ ’