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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here's your problem today. This problem was recently asked by Facebook:

Given a matrix that is organized such that the numbers will always be sorted left to right, and the first number of each row will always be greater than the last element of the last row (mat[i][0] > mat[i - 1][-1]), search for a specific value in the matrix and return whether it exists.

Here's an example and some starter code.

def searchMatrix(mat, value):
  # Fill this in.
  
mat = [
    [1, 3, 5, 8],
    [10, 11, 15, 16],
    [24, 27, 30, 31],
]

print(searchMatrix(mat, 4))
# False

print(searchMatrix(mat, 10))
# True