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推廣網站開發,包含 Laravel 和 Kotlin 後端撰寫、自動化測試、讀書心得等。Taiwan Kotlin User Group 管理員。

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Hi, here's your problem today. This problem was recently asked by AirBNB:

Given a non-empty list of words, return the k most frequent words. The output should be sorted from highest to lowest frequency, and if two words have the same frequency, the word with lower alphabetical order comes first. Input will contain only lower-case letters.


Input: ["daily", "interview", "pro", "pro", 
"for", "daily", "pro", "problems"], k = 2
Output: ["pro", "daily"]
class Solution(object):
  def topKFrequent(self, words, k):
    # Fill this in.

words = ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"]
k = 2
print(Solution().topKFrequent(words, k))
# ['pro', 'daily']