Kotlin Kata - Fizz Buzz

Given an integer n, return a string array answer (1-indexed) where:

• answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
• answer[i] == "Fizz" if i is divisible by 3.
• answer[i] == "Buzz" if i is divisible by 5.
• answer[i] == i if non of the above conditions are true.

Example 1:

Input: n = 3 Output: ["1","2","Fizz"]

Example 2:

Input: n = 5 Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15 Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

class Solution {
    fun fizzBuzz(n: Int): List<String> {
        
    }
}

解答

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這題題目的邏輯很單純

class Solution {
    fun fizzBuzz(n: Int): List<String> {
        val list = mutableListOf<String>()
        for (i in 1..n) {
            if(i % 15 == 0) {
                list.add("FizzBuzz")
                continue
            }
            if(i % 5 == 0) {
                list.add("Buzz")
                continue
            }
            if(i % 3 == 0) {
                list.add("Fizz")
                continue
            }
            list.add(i.toString())
        }
        return list
    }
}

利用 Kotlin 的 map 和 when 可以寫得更加簡潔

class Solution {
    fun fizzBuzz(n: Int) = (1..n).map {
        when {
            it % 15 == 0 -> "FizzBuzz"
            it % 5 == 0 -> "Buzz"
            it % 3 == 0 -> "Fizz"
            else -> it.toString()
        }
    }
}

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